判断1000年---2000年之间的闰年

#include<stdio.h>
int main()
{
		int count = 0;
		int year = 0;
		for (year = 1000; year <= 2000; year++)
		{
			if ((year % 4 == 0) && (year % 100 != 0) || (year % 400 == 0))
			{
				printf("%d ", year);
				count++;
			}
		}
		printf("count = %d\n", count);
		system("pause");
		return 0;
	
}

来源：CSDN

作者：流年碎雨

链接：https://blog.csdn.net/weixin_40123831/article/details/79620319