How to convert some character into five digit unicode one in Python 3.3?

问题

I'd like to convert some character into five digit unicode on in Python 3.3. For example,

import re
print(re.sub('a', u'\u1D15D', 'abc' ))

but the result is different from what I expected. Do I have to put the character itself, not codepoint? Is there a better way to handle five digit unicode characters?

回答1:

Python unicode escapes either are 4 hex digits (\uabcd) or 8 (\Uabcdabcd); for a codepoint beyond U+FFFF you need to use the latter (a capital U), make sure to left-fill with enough zeros:

>>> '\U0001D15D'
'𝅝'
>>> '\U0001D15D'.encode('unicode_escape')
b'\\U0001d15d'

(And yes, the U+1D15D codepoint (MUSICAL SYMBOL WHOLE NOTE) is in the above example, but your browser font may not be able to render it, showing a place-holder glyph (a box or question mark) instead.

Because you used a \uabcd escape, you replaced a in abc with two characters, the codepoint U+1D15 (ᴕ, latin letter small capital ou), and the ASCII character D. Using a 32-bit unicode literal works:

>>> import re
>>> print(re.sub('a', '\U0001D15D', 'abc' ))
𝅝bc
>>> print(re.sub('a', u'\U0001D15D', 'abc' ).encode('unicode_escape'))
b'\\U0001d15dbc'

where again the U+1D15D codepoint could be displayed by your font as a placeholder glyph instead.

回答2:

By the way, you do not need the re module for this. You could use str.translate:

>>> 'abc'.translate({ord('a'):'\U0001D15D'})
'𝅝bc'

来源：https://stackoverflow.com/questions/14624765/how-to-convert-some-character-into-five-digit-unicode-one-in-python-3-3