Define the selected option with the old input in Laravel / Blade

I have this code:

<select required="required" class="form-control" name="title">
    <option></option>
    @foreach ($titles as $key => $val)
        @if (stristr($key, 'isGroup'))
            <optgroup label="{{ $val }}">
        @else
        <option value="{{ $key }}">{{ $val }}</option>
        @endif
    @endforeach
    </select>

So when the form have errors i use the line Redirect::route('xpto')->withInput()->withErrors($v). But i can't re-populate the select fields. Any way to do this without using JavaScript for example?

Also, you can use the ? operator to avoid having to use @if @else @endif syntax. Change:

@if (Input::old('title') == $key)
      <option value="{{ $key }}" selected>{{ $val }}</option>
@else
      <option value="{{ $key }}">{{ $val }}</option>
@endif

Simply to:

<option value="{{ $key }}" {{ (Input::old("title") == $key ? "selected":"") }}>{{ $val }}</option>

The solution is to compare Input::old() with the $keyvariable.

@if (Input::old('title') == $key)
      <option value="{{ $key }}" selected>{{ $val }}</option>
@else
      <option value="{{ $key }}">{{ $val }}</option>
@endif

After Playing around a bit I came up with this and it seems to work just splendidly

<select name="options[]" id="options" class="form-control" multiple>
    @foreach($settings->includes->get('optionList') as $option)
        <option value="{{ $option->id }}" {{ (collect(old('options'))->contains($option->id)) ? 'selected':'' }}>{{ $option->name }}</option>
    @endforeach
</select>

I may be 100% wrong in leveraging the collect function but it works fine on many of my tests. After seeing a few other posts on the site I saw someone recommend leveraging the in_array($needle, $array) function but after noticing that if my old('options') was null it would error out because it requires in_array requires, bet you guessed an array. So after finding the solution to that albeit ugly solution I played with the collect method because after all we are using larval right! well anyway the ugly solution is as follows

@if (old("options")){{ (in_array($option->id, old("options")) ? "selected":"") }}@endif

inline but man that looks ugly to me so long story short I am using the following instead

{{ (collect(old('options'))->contains($option->id)) ? 'selected':'' }}

Hope this helps others!!

This does not seem to work for a non multiple select field ill get back with one that does work for that though.

G-Rajendra

<select name="gender" class="form-control" id="gender">
                                <option value="">Select Gender</option>
                                <option value="M" @if (old('gender') == "M") {{ 'selected' }} @endif>Male</option>
                                <option value="F" @if (old('gender') == "F") {{ 'selected' }} @endif>Female</option>
                            </select>

Best way to do is following

<select class="form-control" name="team" id="team">
 <option value="">---------Choose Team---------</option>
       @foreach($teams as $team)
<option value="{{$team->id}}" {{(old('team')==$team->id)? 'selected':''}}>{{$team->name}}</option>

@endforeach
</select>

eg.<select name="title">
<option value="1"  {{ old('title') == 1 ? 'selected' : '' }}>
    Item 1
</option>
<option value="2" {{ old('title') == 2 ? 'selected' : '' }}>
    Item 2
</option>

</select>

Instead of using Input class you can also use old() helper to make this even shorter.

<option {{ old('name') == $key ? "selected" : "" }} value="{{ $value }}">

      <select class="form-control" name="kategori_id">
        <option value="">-- PILIH --</option>
        @foreach($kategori as $id => $nama)
            @if(old('kategori_id', $produk->kategori_id) == $id )
            <option value="{{ $id }}" selected>{{ $nama }}</option>
            @else
            <option value="{{ $id }}">{{ $nama }}</option>
            @endif
        @endforeach
        </select>

<option value="{{ $key }}" {{ Input::old('title') == $key ? 'selected="selected"' : '' }}>{{ $val }}</option>

My solution here is to loop, just to avoid duplicate option

                            <select class="form-control" name="status" >
                              <?php $lists = ['Current', 'Win', 'Lose']; ?>

                              @foreach($lists as $list)
                              <option value={{$list}} {{(old('status') == $list?'selected':'')}} >{{$list}}</option>
                              @endforeach

                            </select>

<select>
    @if(old('value') =={{$key}})
     <option value="value" selected>{{$value}}</option>
    @else
     <option value="value">{{$value}}</option>
    @endif
</select>

Okay, my 2 cents, using the default value of Laravel's old() function.

<select name="type">
    @foreach($options as $key => $text)
        <option @if((int) old('type', $selectedOption) === $key) selected @endif value="{{ $key }}">{{ $text }}</option>
    @endforeach
</select>

This is quite simple to understand and implement.

 <select class="form-control m-input m-input--air">
     @foreach ($countries as $key)
        @if( $key->name == $user->country )
            <option value="{{ $key->name }}" selected="selected"> {{ $key->name }}</option>
        @else
            <option value="{{ $key->name }}"> {{ $key->name }}</option>
        @endif
     @endforeach   
 </select>

来源：https://stackoverflow.com/questions/29148274/define-the-selected-option-with-the-old-input-in-laravel-blade

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laravel

laravel-4

blade