问题
I am writing an extension method for parsing JSON string for any given type. I wanted to use the method on types instead of instances like many examples we already know, but I somewhat feel it is not supported by Visual Studio. Can someone enlighten me here? The following is the method:
public static T ParseJson<T>(this T t, string str) where T: Type
{
if (string.IsNullOrEmpty(str)) return null;
var serializer = new JavaScriptSerializer();
var obj = serializer.Deserialize<T>(str);
return obj;
}
I want to call the method in this fashion:
var instance = MyClass.ParseJson(text);
Thanks
回答1:
The short answer is it cannot be done; extension methods need to work on an instance of something.
回答2:
To use the extension method, you would have to do:
var instance = typeof(MyClass).ParseJson(text);
The token "MyClass" is not a Type instamce intself, but using typeof will get you a Type to operate on. But how is this any better than:
var instance = JsonUtility.ParseJson<MyClass>(text);
Edit: Actually, the code for the extension method still would not do what you wanted. It will always return a "Type" object, not an instance of that Type.
回答3:
You can't create extension methods that apply to the type itself. They can only be called on instances of a type.
回答4:
As stated in the accepted answer, you can't. However, provided that you have an extension method that can be called from an instance of T:
public static T ParseJson<T>(this T t, string s)
You could write a utility method like this:
public static T ParseJson<T>(string s)
where T: new()
=> new(T).ParseJson(s);
And call it like this:
var t = Utilities.ParseJson<T>(s);
I am afraid that's the best you can do...
来源:https://stackoverflow.com/questions/1848411/how-to-create-extension-methods-for-types