Can I adjust a CGRect with a UIEdgeInsets?

Question

I've got a CGRect, and I'd like to adjust it with a UIEdgeInsets.

It seems like perhaps there might be a built in function that does this. I've looked for a CGRectAdjustByInsets or functions with some other CGRect… prefix, but I didn't find anything.

Should I code my own?

Answer 1

TL;DR

Swift 4.2 use theRect.inset(by: theInsets).

Objective c use UIEdgeInsetsInsetRect(theRect, theInsets)

Example

// CGRectMake takes: left, bottom, width, height.
const CGRect originalRect = CGRectMake(0, 0, 100, 50);

// UIEdgeInsetsMake takes: top, left, bottom, right.
const UIEdgeInsets insets = UIEdgeInsetsMake(10, 10, -20, -20);

// Apply the insets…
const CGRect adjustedRect = UIEdgeInsetsInsetRect(originalRect, insets);

// What's the result?
NSLog(@"%@ inset by %@ is %@", 
      NSStringFromCGRect(originalRect),
      NSStringFromUIEdgeInsets(insets),
      NSStringFromCGRect(adjustedRect));

// Logs out…
// {{0, 0}, {100, 50}} inset by {10, 10, -20, -20} is {{10, 10}, {110, 60}}

Explanation

• A positive inset moves the rectangle's edge inwards (towards the rectangle middle).
• A negative inset moves the edge outward (away from the rectangle middle).
• A zero inset will leaves the edge alone.

Tell Me More

Further useful functions for operating on CGRects are covered by this note.

Answer 2

2018 ... Swift4

Say you want the bounds,

but for example less two pixels on the bottom:

let ei = UIEdgeInsetsMake(0, 0, 2, 0)   // top-left-bottom-right
let smaller = UIEdgeInsetsInsetRect(bounds, ei)

That's it.

If you prefer to write it as one line, it's just

Take two off the bottom:

let newBounds = UIEdgeInsetsInsetRect(bounds, UIEdgeInsetsMake(0, 0, 2, 0))

Cheers

Answer 3

Still 2018 ... Swift 4.2

I guess the new way looks better...

let newCGRect = oldCGRect.inset(by: UIEdgeInsets(top: 0, left: 8, bottom: 0, right: 8))