HTML5 form validation pattern alphanumeric with spaces?

Question

I have the following input tag in my html5 form:

<p>
    <label>Company Name*</label>
    <input type="text" name="name" class="field" required pattern="[a-zA-Z0-9]+" />
</p>

This works just fine checking if the company name consists out of alphanumeric characters. But of course I want to allow spaces in the company name. I need to know what I should add to the pattern.

Answer 1

How about adding a space in the pattern attribute like pattern="[a-zA-Z0-9 ]+". If you want to support any kind of space try pattern="[a-zA-Z0-9\s]+"

Answer 2

My solution is to cover all the range of diacritics:

([A-z0-9À-ž\s]){2,}

A-z - this is for all latin characters

0-9 - this is for all digits

À-ž - this is for all diacritics

\s - this is for spaces

{2,} - string needs to be at least 2 characters long

Answer 3

To avoid an input with only spaces, use: "[a-zA-Z0-9]+[a-zA-Z0-9 ]+".

eg: abc | abc aBc | abc 123 AbC 938234

To ensure, for example, that a first AND last name are entered, use a slight variation like

"[a-zA-Z]+[ ][a-zA-Z]+"

eg: abc def

Answer 4

It's quite an old question, but in case it could be useful for anyone, starting from a combination of good responses found here, I've ended using this pattern:

pattern="([^\s][A-z0-9À-ž\s]+)"

It will require at least two characters, making sure it does not start with an empty space but allowing spaces between words, and also allowing special characters such as ą, ó, ä, ö.

Answer 5

Use this code to ensure the user doesn't just enter spaces but a valid name:

pattern="[a-zA-Z][a-zA-Z0-9\s]*"

Answer 6

Use Like below format code

$('#title').keypress(function(event){
    //get envent value       
    var inputValue = event.which;
    // check whitespaces only.
    if(inputValue == 32){
        return true;    
    }
     // check number only.
    if(inputValue == 48 || inputValue == 49 || inputValue == 50 || inputValue == 51 || inputValue == 52 || inputValue == 53 ||  inputValue ==  54 ||  inputValue == 55 || inputValue == 56 || inputValue == 57){
        return true;
    }
    // check special char.
    if(!(inputValue >= 65 && inputValue <= 120) && (inputValue != 32 && inputValue != 0)) { 
        event.preventDefault(); 
    }
})

Answer 7

Use below code for HTML5 validation pattern alphanumeric without / with space :-

for HTML5 validation pattern alphanumeric without space :- onkeypress="return event.charCode >= 48 && event.charCode <= 57 || event.charCode >= 97 && event.charCode <= 122 || event.charCode >= 65 && event.charCode <= 90"

for HTML5 validation pattern alphanumeric with space :-

onkeypress="return event.charCode >= 48 && event.charCode <= 57 || event.charCode >= 97 && event.charCode <= 122 || event.charCode >= 65 && event.charCode <= 90 || event.charCode == 32"