Layer multiple BufferedImages on top of one another?

问题

I have multiple transparent BufferedImage instances which I'd like to layer on top of each other (aka Photoshop layers) and bake into one BufferedImage output. How do I do this?

回答1:

I would say the best bet would be to take the buffered images, and create an additional one in order to have an object to append to. Then simply use the Graphics.drawImage() to place them on top of each other.

So something along these lines:

BufferedImage a = ImageIO.read(new File(filePath, "a.png"));
BufferedImage b = ImageIO.read(new File(filePath, "b.png"));
BufferedImage c = new BufferedImage(a.getWidth(), a.getHeight(), BufferedImage.TYPE_INT_ARGB);

Graphics g = c.getGraphics();
g.drawImage(a, 0, 0, null);
g.drawImage(b, 0, 0, null);

回答2:

Let's pretend that the first BufferedImage is named bi1 and the second bi2, while the image you want to layer them onto is target.

BufferedImage target=new BufferedImage(width,height,BufferedImage.TYPE_INT_ARGB);
Graphics2D targetGraphics=target.createImage();
targetGraphics.drawImage(bi1,0,0,null);//draws the first image onto it

int[] pixels2=((DataBufferInt) bi2.getRaster().getDataBuffer()).getData();
int[] pixelsTgt=((DataBufferInt) target.getRaster().getDataBuffer()).getData();
for(int a=0;a<pixels2.length;a++)
{
     pixelsTgt[a]+=pixels2[a];//this adds the pixels together
}

Make sure that all three BufferedImage objects are of TYPE_INT_ARGB so that alpha is turned on. This may not give you the exact results that you had wanted if the two added together are more than the max integer, so you might want to add in something to help fix that. Pixels use bit shifts to add to colors with the integer ordered as AARRGGBB.

回答3:

Also consider the AlphaComposite modes available to the graphics context, discussed here.

来源：https://stackoverflow.com/questions/11148453/layer-multiple-bufferedimages-on-top-of-one-another

标签

java

bufferedimage