Jackson JSON Deserialization with Root Element

问题

I am having a question with Jackson that I think should be simple to solve, but it is killing me.

Let\'s say I have a java POJO class that looks like this (assume Getters and Setters for me):

class User {
    private String name;
    private Integer age;
}

And I want to deserialize JSON that looks like this into a User object:

{
  \"user\":
    {
      \"name\":\"Sam Smith\",
      \"age\":1
  }
}

Jackson is giving me issues because the User is not the first-level object in the JSON. I could obviously make a UserWrapper class that has a single User object and then deserialize using that but I know there must be a more elegant solution.

How should I do this?

回答1:

edit: this solution only works for jackson < 2.0

For your case there is a simple solution:

You need to annotate your model class with @JsonRootName(value = "user");
You need to configure your mapper with om.configure(Feature.UNWRAP_ROOT_VALUE, true); (as for 1.9) and om.configure(DeserializationFeature.UNWRAP_ROOT_VALUE, true); (for version 2).

That's it!

@JsonRootName(value = "user")
public static class User {
    private String name;
    private Integer age;

    public String getName() {
        return name;
    }

    public void setName(final String name) {
        this.name = name;
    }

    public Integer getAge() {
        return age;
    }

    public void setAge(final Integer age) {
        this.age = age;
    }

    @Override
    public String toString() {
        return "User [name=" + name + ", age=" + age + "]";
    }

}

ObjectMapper om = new ObjectMapper();
om.configure(Feature.UNWRAP_ROOT_VALUE, true);
System.out.println(om.readValue("{  \"user\":    {      \"name\":\"Sam Smith\",      \"age\":1  }}", User.class));

this will print:

User [name=Sam Smith, age=1]

来源：https://stackoverflow.com/questions/11704255/jackson-json-deserialization-with-root-element

标签

java

json

jackson

pojo