问题
I can compare {} to true or false or itself, but comparison to null or undefined gives a syntax error. Is this because {} is an object value and not a reference? It feels weird that it would be a Syntax Error instead of some kind of runtime type error, or just work.
To clarify, I'm curious why this is a SyntaxError, mostly compared to doing {} == {} which is not only not a SyntaxError, but no error at all.
回答1:
There are two main contexts when parsing code: the expression context and the statement context. The body of a function for example is a statement context, the right side of an assignment is an expression context. To distinguish both makes sense to forbid things like:
 if( if(true) ) alert("nonsense");
Now REPL have a really difficult task: On the one hand, they have to parse functions and codeblocks that get entered, and on the other hand you sometimes just want to check how a certain object look like. Therefore this:
 { a: 1, b: 2 }
is actually a SyntaxError in JavaScript, as a { in a statement context starts a block of code, and : is invalid then. However the REPL is clever enough and puts that object into an expression context, and evaluates it as if it would be in parens:
({ a: 1, b: 2 })
the same happens for:
 {} == {}
which is actually also a SyntaxError, however the REPL also moves it into an expression context:
 ({} == {})
That "moving into an expression context" is a complicated task, and it seems as if the REPL just does not see the expression here:
 {} == null
and therefore parses {} as a block. Thats the case because the REPL just naively checks if the first and the last character are { and }, which is the case for {} == {} but not for {} == null.
Relevant part of the chromium sourcecode:
 if (/^\s*\{/.test(text) && /\}\s*$/.test(text))
  text = '(' + text + ')';
executionContext.evaluate(text, "console", !!useCommandLineAPI, false, false, true, printResult);
    来源:https://stackoverflow.com/questions/53306680/why-does-null-give-a-syntaxerror