How to get everything within brackets in golang with regex

问题

I am trying to get everything within the outside brackets of the following sql statement in golang regular expressions.

Categories
(// = outside bracket
PersonID int,
LastName varchar(255),
FirstName varchar(255),
Address varchar(255),
City varchar(255)
)//=outside bracket

how would I use regex to only identify the outer brackets and return everything in between the outside brackets?

回答1:

All you need is to find the first (, then match any characters up to the last ) with

`(?s)\((.*)\)`

Details:

• (?s) - allow . to match any character, including a newline
• \( - a literal ( char
• (.*) - Submatch 1 capturing any zero or more characters
• \) - a literal ) symbol.

See the Go demo:

package main

import (
    "fmt"
    "regexp"
)

func main() {
    s := `Categories
(// = outside bracket
PersonID int,
LastName varchar(255),
FirstName varchar(255),
Address varchar(255),
City varchar(255)
)//=outside bracket`
    re := regexp.MustCompile(`(?s)\((.*)\)`)

    m := re.FindAllStringSubmatch(s,-1)
    fmt.Printf("Capture value: %s", m[0][1])
}

来源：https://stackoverflow.com/questions/39488210/how-to-get-everything-within-brackets-in-golang-with-regex