Violating the one definition rule by simply linking dynamically

痞子三分冷 提交于 2021-02-11 08:07:37

问题


Question: Are dynamically linked C++ programs on ELF platforms always on the brink of producing undefined behavior by violating the one definition rule?

More specific: By simply writing a shared library exposing one function

#include <string>
int __attribute__((visibility("default"))) combined_length(const char *s,
                                                           const char *t)
{
    const std::string t1(t);
    const std::string u(s + t1);
    return u.length();
}

and compiling it with GCC 7.3.0 via

$ g++ -Wall -g -fPIC -shared \
      -fvisibility=hidden -fvisibility-inlines-hidden \
      -o liblibrary.so library.cpp

I create a binary which defines a weak symbol for the operator+() of a pointer to a character array and a string:

$ readelf -sW liblibrary.so | grep "_ZStpl"
    24: 0000000000000ee2   202 FUNC    WEAK   DEFAULT   12 _ZStplIcSt11char_traitsIcESaIcEENSt7__cxx1112basic_stringIT_T0_T1_EEPKS5_RKS8_
    ...

But looking at the standard library binary I got

$ readelf -sW /usr/lib/x86_64-linux-gnu/libstdc++.so.6 | grep "_ZStplIcSt11char_traitsIcESaIcEENSt7__cxx1112basic_stringIT_T0_T1_EEPKS5_RKS8_"
  2829: 000000000012b1c0   169 FUNC    WEAK   DEFAULT   13 _ZStplIcSt11char_traitsIcESaIcEENSt7__cxx1112basic_stringIT_T0_T1_EEPKS5_RKS8_@@GLIBCXX_3.4.21

That's the point where I say: Oh my gosh, the symbol inside my library ought to have a version attached to it too!

In the current state I'm fine because I can assume that the standard library binary is built with the same headers as my library. But what happens if the implementers of libstdc++-v3 decide to define a new version of this function and tag it with GLIBCXX_3.4.22? Since the symbol is weak, the runtime linker is free to decide whether it takes the unversioned symbol of my library or the versioned symbol of the libstdc++-v3. If I ship my library to such a system I provoke undefined behavior there. Something symbol versions should have solved for me.

来源:https://stackoverflow.com/questions/52223788/violating-the-one-definition-rule-by-simply-linking-dynamically

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