MongoDB: Find all lower/uppercase duplicates in DB

问题

There is a huge collection with 600.000 documents. Unfortunatly there are duplicates, which I want to find. These duplicates differs only in first letter upper/lower case.

{ key: 'Find me' },
{ key: 'find me' },
{ key: 'Don't find me }, // just one document for this string
{ key: 'don't find me either } // just one document for this string

Now I want to get all duplicates, which means there is an existing uppercase AND lowercase string.

回答1:

In MongoDB, there is a $toLower transformation available that you can use.

Here is a way to output every key appearing more than once (you need to change db.collection by the name of your collection):

db.collection.aggregate([ 
    { $group: 
        { 
            _id: { $toLower: "$key" }, 
            cnt: { "$sum": 1 } 
        }
    },
    { $match: 
        { cnt: {$gt: 1 } } 
    }
])

First, the $group groups the documents by key (case insensitive). The number of documents for each key is accumulated in cnt. For after the $group, you end up with something like:

 {"key": "find me", "cnt": 2}
 {"key": "other key", "cnt": 1}
 ...

Then, the $match filters those results, retaining only the ones with a cnt greated than 1.

Note: above is the code for the mongo shell. You can do pretty much the same from javascript (using the mongodb driver), but you need to add quotes around $group and such.

来源：https://stackoverflow.com/questions/40978162/mongodb-find-all-lower-uppercase-duplicates-in-db