问题
This question already has an answer here:
- How to pass parameters from bash to php script? 3 answers
I need a shell script which has a loop. In each loop iteration it needs to call a PHP file with some parameters. Is there any way to do it?
回答1:
In your php file named test.php, for example
<?php
//like programs in c language, use $argc, $argv access command line argument number and arguments, uncomment below two line to dump $argc and $argv
//var_dump($argc); //an integer
//var_dump($argv); //an array with arguments
//use args and do anything you want
echo "do my job\n";
exit(0);
then create a shell script named test.sh
#! `which bash`
php=`which php`
i=10
while [[ $i -ge 0 ]];
do
$php test.php 1 2
((i--))
done
put the two files into the same directory. Then run command in the terminal
bash test.sh
回答2:
If this means a Linux/Unix shell
for i in `seq 4`; do
php myscript.php param1 param2
done
But since PHP has loops too, you can do this in PHP as well.
for ($i = 0; $i < 4; $i++)
system("php myscript.php param1 param2");
回答3:
#!/bin/sh
#
#Script to test for loop
#
#
while [condition]
do
php test.file
done
来源:https://stackoverflow.com/questions/13855666/how-to-call-php-file-from-a-shell-script-file