I have a high-performant function written in Julia, how can I use it from Python?

问题

I have a found a Julia function that nicely does the job I need. How can I quickly integrate it to be able to call it from Python?

Suppose the function is

f(x,y) = 2x.+y

What is the best and most elegent way to use it from Python?

回答1:

Assuming your Python and Julia are installed you need to take the following steps.

Run Julia and install PyCall
```
using Pkg
pkg"add PyCall"
```
Put your code into a Julia package
```
using Pkg
Pkg.generate("MyPackage")
```
In the folder src you will find MyPackage.jl, edit it to look like this:
```
module MyPackage
f(x,y) = 2x.+y
export f
end
```
Install pyjulia
```
python -m pip install julia
```
(On Linux systems you might want to use python3 instead of python command)

For this step note that while an external Python can be used with Julia. However, for a convenience it might be worth to consider using a Python that got installed together with Julia as PyCall. In that case for installation use a command such this one:
```
%HOMEPATH%\.julia\conda\3\python -m pip install julia
```
or on Linux
```
~/.julia/conda/3/python -m pip install julia
```
Note that if you have JULIA_DEPOT_PATH variable defined you can replace %HOMEPATH%\.julia or ~/.julia/ with its value.
Run the appropiate Python and tell it to configure the Python-Julia integration:
```
import julia
julia.install()
```

Now you are ready to call your Julia code:

>>> from julia import Pkg
>>> Pkg.activate(".\\MyPackage") #use the correct path
    Activating environment at `MyPackage\Project.toml`
>>> from julia import MyPackage
>>> MyPackage.f([1,2],5)
    [7,9]

来源：https://stackoverflow.com/questions/64241264/i-have-a-high-performant-function-written-in-julia-how-can-i-use-it-from-python

标签

python

python-3.x

julia

pycall