How to create simple jQuery plugin?

大城市里の小女人 提交于 2019-11-28 01:40:07

For plugin authoring try this way, much more solid:

Edit: Here is working jsFiddle example.


PLUGIN:

(function($){
    $.fn.extend({
        YourPluginName: function(options) {
                var defaults = {
                      howMuch:'600',
                      animation: '',//users can set/change these values
                      speed: 444,
                      etc: ''
                }
        };

       options = $.extend(defaults, options);

       return this.each(function() {
          var $this = $(this);              
          var button = $('a', $this);// this represents all the 'a' selectors;
                                            // inside user's plugin definition.

          button.click(function() {
            $this.animate({'top':options.howMuch});//calls options howMuch value
          });
       });
})(jQuery);

USER'S DOCUMENT:

$(function() {
   $('#plugin').YourPluginName({
     howMuch:'1000' //you can give chance users to set their options for plugins
   });
});

<div id="plugin">
  <a>1</a>
  <a>2</a>
  <a>3</a>
</div>
Gopal Joshi

Here i want to suggest steps to create simple plugin with arguments.

JS

(function($) {
    $.fn.myFirstPlugin = function( options ) {

        // Default params
        var params = $.extend({
            text     : 'Default Title',
            fontsize : 10,
        }, options);
        return $(this).text(params.text);

    }
}(jQuery));

Here, we have added default object called params and set default values of options using extend function. Hence, If we pass blank argument then it will set default values instead otherwise it will set.

HTML

$('.cls-title').myFirstPlugin({ text : 'Argument Title' });

Read more: How to Create JQuery plugin

Original answer Here i want to suggest steps to create simple plugin with arguments

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