python 判断列表的包含关系

 

def is_Sublist(l, s):  
    sub_set = False  
    if s == []:  
        sub_set = True  
    elif s == l:  
        sub_set = True  
    elif len(s) > len(l):  
        sub_set = False  
  
    else:  
        for i in range(len(l)):  
            if l[i] == s[0]:  
                n = 1  
                while (n < len(s)) and (l[i+n] == s[n]):  
                    n += 1  
                  
                if n == len(s):  
                    sub_set = True  
  
    return sub_set  
  
a = [2,4,3,5,7]  
b = [4,3]  
c = [3,7]  
print(is_Sublist(a, b))  
print(is_Sublist(a, c))

 

来源：oschina

链接：https://my.oschina.net/u/4363202/blog/3749775