Regex for removing Commas within brackets

问题

I am stuck at writing the regex which needs me to remove comma inside brackets. The commas outside should stay as is

Here's what I need

Input :(37.400809377128354, -122.05618455969392) , (37.3931723332768, -121.89276292883454)

Output :(37.400809377128354 -122.05618455969392) , (37.3931723332768 -121.89276292883454)

Thanks in Advance!

回答1:

You can use this regex which uses positive look ahead to discard matching a comma that is outside the parenthesis,

,(?=[^()]*\))

Demo

var s = "(37.400809377128354, -122.05618455969392),(37.3931723332768, -121.89276292883454)";
console.log(s.replace(/,(?=[^()]*\))/g, ''));

回答2:

ES '18 Solution using Look-behind Assertions

const s = "(37.400809377128354, -122.05618455969392),(37.3931723332768, -121.89276292883454)";

console.log(
    s.replace(/(?<=\d),/g, '')
);

ECMAScript® 2018 Language Specification

来源：https://stackoverflow.com/questions/54359053/regex-for-removing-commas-within-brackets