Parse date “2020-05-22T12:51:20.765111Z” to Instant in Java [duplicate]

问题

This question already has answers here:

How to validate the DateTime string format “2018-01-22T18:23:00.000Z” in Java? (2 answers)

Closed 7 months ago.

How to parse "2020-05-22T12:51:20.732111Z" to Instant in Java?

I used:

LocalDateTime.parse(
              startTime, DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'", Locale.US))
          .atZone(ZoneId.of("America/Toronto"))
          .toInstant()

but with error:

Exception in thread "main" java.time.format.DateTimeParseException: Text '2020-05-22T12:51:20.732111Z' could not be parsed at index 24
    at java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:1949)
    at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1851)
    at java.time.LocalDateTime.parse(LocalDateTime.java:492)
    at Instant.Main.main(Main.java:54)

回答1:

Use Instant#parse(String):

Instant i = Instant.parse("2020-05-22T12:51:20.732111Z");

And if you want to convert it to your timezone:

ZonedDateTime z = i.atZone(ZoneId.of("America/Toronto"));

Printing it yields:

2020-05-22T08:51:20.732111-04:00[America/Toronto]

来源：https://stackoverflow.com/questions/62675902/parse-date-2020-05-22t125120-765111z-to-instant-in-java