Python: Formatting a string using variable names placeholders

我怕爱的太早我们不能终老 提交于 2021-02-04 14:53:25

问题


Consider the following string building statement:

s="svn cp %s/%s/ %s/%s/" % (root_dir, trunk, root_dir, tag)

Using four %s can be confusing, so I prefer using variable names:

s="svn cp {root_dir}/{trunk}/ {root_dir}/{tag}/".format(**SOME_DICTIONARY)

When root_dir, tag and trunk are defined within the scope of a class, using self.__dict__ works well:

s="svn cp {root_dir}/{trunk}/ {root_dir}/{tag}/".format(**self.__dict__)

But when the variables are local, they are not defined in a dictionary, so I use string concatenation instead:

s="svn cp "+root_dir+"/"+trunk+"/ "+root_dir+"/"+tag+"/"

I find this method quite confusing, but I don't know any way to construct a string using in-line local variables.

How can I construct the string using variable names when the variables are local?

Update: Using the locals() function did the trick.

Note that mixing local and object variables is allowed! e.g.,

s="svn cp {self.root_dir}/{trunk}/ {self.root_dir}/{tag}/".format(**locals())

回答1:


You can use locals() function

s="svn cp {root_dir}/{trunk}/{root_dir}/{tag}/".format(**locals())

EDIT:

Since python 3.6 you can use string interpolation:

s = f"svn cp {root_dir}/{trunk}/{root_dir}/{tag}/"



回答2:


Have you tried s="svn cp {root_dir}/{trunk}/ {root_dir}/{tag}/".format(**locals()) ?




回答3:


less cryptic and faster

"my name is {__name__}".format_map(locals())

str.format_map(mapping)

Similar to str.format(**mapping), except that mapping is used directly and not copied to a dict.



来源:https://stackoverflow.com/questions/17471439/python-formatting-a-string-using-variable-names-placeholders

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