Pass parameters correctly to SqlCommand

大城市里の小女人 提交于 2021-02-04 08:09:30

问题


I have code to insert data to SQL table. The columns have such types:

@param1 datetime,
@param2 nvarchar(50),
@param3 int,
@param4 bit,
@param5 int,
@param6 bit,
@param7 bit,
@param8 varchar(20),
@param9 varchar(20)

This is my method:

try
{
    using (SqlCommand oleDbCommand = new SqlCommand())
    {
        // Set the command object properties
        oleDbCommand.Connection = new SqlConnection(connectionString);
        oleDbCommand.CommandType = CommandType.StoredProcedure;
        oleDbCommand.CommandText = "[dbo].[InsertRow]";
        // Add the input parameters to the parameter collection
        // m.param1 is of DateTime type, m.param2 of string type, m.param3 of int type, etc.
        oleDbCommand.Parameters.AddWithValue("@param1", m.param1);
        oleDbCommand.Parameters.AddWithValue("@param2", m.param2);
        oleDbCommand.Parameters.AddWithValue("@param3", m.param3);
        oleDbCommand.Parameters.AddWithValue("@param4", m.param4);
        oleDbCommand.Parameters.AddWithValue("@param5", m.param5);
        oleDbCommand.Parameters.AddWithValue("@param6", m.param6);
        oleDbCommand.Parameters.AddWithValue("@param7", m.param7);
        oleDbCommand.Parameters.AddWithValue("@param8", m.param8);
        oleDbCommand.Parameters.AddWithValue("@param9", m.param9);
        // Open the connection, execute the query and close the connection.
        oleDbCommand.Connection.Open();
        oleDbCommand.ExecuteNonQuery();
        oleDbCommand.Connection.Close();
    }
}
catch (Exception ex)
{
    MessageBox.Show(ex.Message);
    return false;
}

I have two but related questions:

  • am I passing parameters correctly? Or do I need casts? (please see the column types in the beginning of the question).
  • how to correctly handle closing of database? In case also of some exception?

回答1:


I would do as below

try
{   
    using (var conn = new SqlConnection(connectionString))
    using (var command = new SqlCommand("[dbo].[InsertRow]", conn) { 
                        CommandType = CommandType.StoredProcedure }) {
        conn.Open();
        command.Parameters.Add("@param1", SqlDbType.DateTime).Value = m.param1;
        command.Parameters.Add("@param2", SqlDbType.NVarChar, 50).Value = m.param2;
        command.Parameters.Add("@param3", SqlDbType.Int).Value = m.param3;
        command.Parameters.Add("@param4", SqlDbType.Bit).Value = m.param4;
        command.Parameters.Add("@param5", SqlDbType.Int).Value = m.param5;
        command.Parameters.Add("@param6", SqlDbType.Bit).Value = m.param6;
        command.Parameters.Add("@param7", SqlDbType.Bit).Value = m.param7;
        command.Parameters.Add("@param8", SqlDbType.VarChar, 20).Value = m.param8;
        command.Parameters.Add("@param9", SqlDbType.VarChar, 20).Value = m.param9;
        command.ExecuteNonQuery();
    }
}
catch (Exception ex)
{
    MessageBox.Show(ex.Message);
    return false;
}



回答2:


AddWithValue tries to assigns the value by unboxing an object in the c# type based on the database field's type.

try
{
    using (var oleDbConnection = new SqlConnection(connectionString))
    {
        // Set the command object properties
        SqlCommand oleDbCommand = new SqlCommand()
        oleDbCommand.Connection = oleDbConnection;
        oleDbCommand.CommandType = CommandType.StoredProcedure;
        oleDbCommand.CommandText = "[dbo].[InsertRow]";
        // Add the input parameters to the parameter collection
        // m.param1 is of DateTime type, m.param2 of string type, m.param3 of int type, etc.
        oleDbCommand.Parameters.AddWithValue("@param1", m.param1);
        oleDbCommand.Parameters.AddWithValue("@param2", m.param2);
        oleDbCommand.Parameters.AddWithValue("@param3", m.param3);
        oleDbCommand.Parameters.AddWithValue("@param4", m.param4);
        oleDbCommand.Parameters.AddWithValue("@param5", m.param5);
        oleDbCommand.Parameters.AddWithValue("@param6", m.param6);
        oleDbCommand.Parameters.AddWithValue("@param7", m.param7);
        oleDbCommand.Parameters.AddWithValue("@param8", m.param8);
        oleDbCommand.Parameters.AddWithValue("@param9", m.param9);
        // Open the connection, execute the query and close the connection.
        oleDbCommand.Connection.Open();
        oleDbCommand.ExecuteNonQuery();
    }
}
catch (Exception ex)
{
    MessageBox.Show(ex.Message);
    return false;
}

using statement adds itself the correct connection handling after its use.



来源:https://stackoverflow.com/questions/26461949/pass-parameters-correctly-to-sqlcommand

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