Regular Expression Match And Compare Captured Groups

问题

I'm trying to match some strings of the pattern:

event = sometext1 name = prefix sometext2

I want to match all cases that sometext1 and sometext2 are different. How should I do it with regular expression? Thanks!

回答1:

You can use this regex:

event += +(\w+) +name+ = +\w+ +((?!\1)\w+)\b

RegEx Demo

回答2:

Use a backreference like this:

^event = ([^\s]+) name = prefix (?!\1).+$

Debuggex Demo

来源：https://stackoverflow.com/questions/28889304/regular-expression-match-and-compare-captured-groups