Google sheets easily put a similar sheet name in a variable

问题

May I ask if there is a way for me to easily put all the sheet name (well, most likely SF2 sheet) in this variable? I do have like 10 similar SF2 sheets.

var sheetNames = ["School Form 1 (SF1)", "SEPT-School Form 2 (SF2)", "OCT-School Form 2 (SF2)", "OCT-School Form 2 (SF2)", ........, "School Form 5 (SF5)"];

I'm currently working in hiding rows. Here's the code:

var startRow = 11;
var colToCheck = 2;

// This script is the same with your "HideRows".
function script_HideRows() {
  var sheetNames = ["School Form 1 (SF1)", "SEPT-School Form 2 (SF2)", "OCT-School Form 2 (SF2)", "School Form 5 (SF5)"];
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  ss.getSheets().forEach(sheet => {
    var sheetName = sheet.getSheetName();
    if (sheetNames.includes(sheetName)) {
      var numRows = sheet.getLastRow();
      var elements = sheet.getRange(startRow, colToCheck, numRows).getValues();
     
      for (var i=0; i < elements.length; i++) {
        if (shouldHideRow(sheet, i, elements[i][0])) {
          sheet.hideRows(startRow + i);
        }
      }
      // Hide the rest of the rows
      var totalNumRows = sheet.getMaxRows();
      if (totalNumRows > numRows)
        sheet.hideRows(numRows+1, totalNumRows - numRows);
    }
  });
}

What should I put to make the script still work in all of the sheets? Should I just enter it all or is there an easy way?

回答1:

TDLR

Explanation:

Get all the sheet names,

replace:

var sheetNames = ["School Form 1 (SF1)", "SEPT-School Form 2 (SF2)", "OCT-School Form 2 (SF2)", "School Form 5 (SF5)"];

with:

var sheetNames = ss.getSheets().map(sh=>sh.getSheetName());

Then, if you only want to get the sheets that contain SF2:

replace:

if (sheetNames.includes(sheetName))

with:

if (sheetNames.includes('SF2'))

If you want to have multiple filters, try this logic:

if (sheetNames.includes('SF2') || sheetNames.includes('SF5'))

The latter will evaluate to true for all the sheets that contain SF2 or SF5.

Solution 1:

var startRow = 11;
var colToCheck = 2;

// This script is the same with your "HideRows".
function script_HideRows() {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheetNames = ss.getSheets().map(sh=>sh.getSheetName());
  
  sheetNames.forEach(sheetName => {
    var sheet = ss.getSheetByName(sheetName);                 
    if (sheetName.includes('SF2')) {
      var numRows = sheet.getLastRow();
      var elements = sheet.getRange(startRow, colToCheck, numRows).getValues();
     
      for (var i=0; i < elements.length; i++) {
        if (shouldHideRow(sheet, i, elements[i][0])) {
          sheet.hideRows(startRow + i);
        }
      }
      // Hide the rest of the rows
      var totalNumRows = sheet.getMaxRows();
      if (totalNumRows > numRows)
        sheet.hideRows(numRows+1, totalNumRows - numRows);
    }
  });
}

Solution 2:

Another approach would be to filter on SF2 at the point you define the sheetNames array. Using this approach you don't need to iterate over all sheets, but only the relevant ones (that contain SF2). Therefore, you don't need an if condition in the forEach loop.

var startRow = 11;
var colToCheck = 2;

// This script is the same with your "HideRows".
function script_HideRows() {
  var ss = SpreadsheetApp.getActiveSpreadsheet();  
  var sheetNames = ss.getSheets().map(sh=>sh.getSheetName())
                   .filter(sheetName=>sheetName.includes('SF2'))
  
  sheetNames.forEach(sheetName => {
    var sheet = ss.getSheetByName(sheetName);                 
      var numRows = sheet.getLastRow();
      var elements = sheet.getRange(startRow, colToCheck, numRows).getValues();
     
      for (var i=0; i < elements.length; i++) {
        if (shouldHideRow(sheet, i, elements[i][0])) {
          sheet.hideRows(startRow + i);
        }
      }
      // Hide the rest of the rows
      var totalNumRows = sheet.getMaxRows();
      if (totalNumRows > numRows)
        sheet.hideRows(numRows+1, totalNumRows - numRows); 
  });
}

Using the same logic as before, if you want multiple filters, do that:

var sheetNames = ss.getSheets().map(sh=>sh.getSheetName())
                   .filter(sheetName=>sheetName.includes('SF2') || sheetName.includes('SF5'))

来源：https://stackoverflow.com/questions/64708355/google-sheets-easily-put-a-similar-sheet-name-in-a-variable

标签

javascript

google-apps-script

google-sheets