问题
I am working on a small React project where I am stuck at this point. I need to make a grouping based on array object key.
Below is the Array:
let addOnFeatures = [
{"name": "feature1", id: 101, cost: 100},
{"name": "feature2", id: 102, cost: 200},
{"name": "feature1", id: 103, cost: 300},
{"name": "feature3", id: 104, cost: 40}
]
I need to make a grouping based on name key so that every id related to common name should be displayed on its own tab.
Expected output should be like
*uniqueFeaturename
id: cost
Example:
1. feature1
101 : 100
103 : 300
2. feature2
102 : 200
3. feature3
104: 40
回答1:
Just make use of Array.prototype.reduce
and add elements to object like
let addOnFeatures = [
{"name": "feature1", id: 101, cost: 100},
{"name": "feature2", id: 102, cost: 200},
{"name": "feature1", id: 103, cost: 300},
{"name": "feature3", id: 104, cost: 40}
]
const res = addOnFeatures.reduce((acc, item) => {
if(acc[item.name]) {
acc[item.name] = {...acc[item.name], [item.id]: item.cost};
} else {
acc[item.name] = {[item.id]: item.cost};
}
return acc;
}, {});
console.log(res);
回答2:
One solution can be this:
let addOnFeatures = [
{"name": "feature1", id: 101, cost: 100},
{"name": "feature2", id: 102, cost: 200},
{"name": "feature1", id: 103, cost: 300},
{"name": "feature3", id: 104, cost: 40}
];
var res={};
addOnFeatures.forEach(i=>{
if(!res[i.name]){
res[i.name] = [{id: i.id, cost:i.cost}]
}else{
res[i.name].push({id: i.id, cost:i.cost})
}
}
);
console.log(res)
let addOnFeatures = [
{"name": "feature1", id: 101, cost: 100},
{"name": "feature2", id: 102, cost: 200},
{"name": "feature1", id: 103, cost: 300},
{"name": "feature3", id: 104, cost: 40}
];
var res2={};
addOnFeatures.forEach(i=>{
res2[i.name] = res2[i.name] ? [...res2[i.name],...[{id: i.id, cost:i.cost}]] :[...[{id: i.id, cost:i.cost}]]
}
);
console.log(res2)
来源:https://stackoverflow.com/questions/62058409/grouping-based-on-unique-key-in-array-of-object