Passing quoted arguments to C program in a shell script

问题

I have a C program "main" which gets the following parameters:

"a b c d ..." e f g

That's a total of 4 parameters, because of the quotation. I have a text file which each line has these 4 parameters. I made a shell script to run the C program for each of the parameters:

#!/bin/bash
while read line
do
    ./main "$line"
done < $1

The problem is that the C program is recognizing the first parameter, which is quoted, as several separated parameters, as if the quote was being ignored. Among the many things I've tried, it's worth mentioning that I tried changing each quotation in the file to \" and even remove the quotation from the call (./main $line).

回答1:

#!/bin/bash
while read line
do
    eval set -- $line
    ./main "$@"
done < $1

来源：https://stackoverflow.com/questions/20085303/passing-quoted-arguments-to-c-program-in-a-shell-script