c popen won't catch stderr

问题

I\'m trying to use popen() to catch the stderr of a call, but of course it doesn\'t seem to be doing that. Any ideas?

My code looks more or less like this:

popen(\"nedit\", \"r\");

But I\'m getting all this garbage about non-utf8 on my screen...

回答1:

popen gives you a file handle on a process' stdout, not its stderr. Its first argument is interpreted as a shell command, so you can do redirections in it:

FILE *p = popen("prog 2>&1", "r");

or, if you don't want the stdout at all,

FILE *p = popen("prog 2>&1 >/dev/null", "r");

(Any other file besides /dev/null is acceptable as well.)

回答2:

If you want to discard all of the error messages, then you can use:

popen("nedit 2>/dev/null", "r");

来源：https://stackoverflow.com/questions/6900577/c-popen-wont-catch-stderr