问题
I need to print out a list of common factors for two numbers
def print_nums(x, y):
for i in range(1, x + 1):
if x % i == 0:
print(i)
for t in range(1, y + 1):
if y % t == 0:
print(t)
number = int(input("Enter a number: "))
number2 = int(input("Enter a second number: "))
print("Common factors are: ".format(number, number2))
print_nums(number, number2)
It prints out both lists but not the common factors of each
回答1:
def print_nums(x, y):
zet = []
for i in range(1, x + 1):
if x % i == 0:
#print(i)
zet.append(i)
for t in range(1, y + 1):
if y % t == 0 and t in zet:
print(t)
number = int(input("Enter a number: "))
number2 = int(input("Enter a second number: "))
print("Common factors are:")
print_nums(number, number2)
Example of running the code:
Enter a number: 24
Enter a second number: 18
Common factors are:
1
2
3
6
回答2:
Your code just prints factors, not common factors. You could loop over x and y's common range and check if i is a factor of both:
def common_factors(x, y):
for i in range(2, min(x, y)+1): # 1 is trivial, so ignore it
if x % i == 0 and y % i == 0: # If x and y are both multiples of i
yield i
print(list(common_factors(9, 12))) # -> [3]
回答3:
basically same thought as the above solutions..but a nifty function to basically check for only items in the list which are non-unique..like the opposite of set...this returns common factors because they will occur more than once
from iteration_utilities import duplicates, unique_everseen
facs=[]
def print_nums(x, y, facs):
for i in range(1, x + 1):
if x % i == 0:
facs.append(i)
for t in range(1, y + 1):
if y % t == 0:
facs.append(t)
return list(unique_everseen(duplicates(facs)))
来源：https://stackoverflow.com/questions/57780560/how-do-i-print-out-a-list-of-common-factors-for-two-numbers