Why is a variable not updating after changing its dependent variable? [duplicate]

╄→гoц情女王★ 提交于 2021-01-27 11:22:50

问题


I don't understand why the variable 'y' doesn't update when I change the x? (The 'y' variable is dependent on 'x' right?)

x = 5
y = x*2

print(x)
print(y)

x = 3

# Expect it to print '3' and '6' instead it print '3' and '10'
print(x)
print(y)

回答1:


(The 'y' variable is dependent on 'x' right?

No.

Few programming languages have dependent / computed variables[0] and Python is not one of them[1]. When y = x*2 is executed, the expression on the right-side of the = is fully evaluated and the result set as the value of y. y is thereafter independent from x[2].

Generally speaking, if you want y to be a function of x... you define it as a function of x:

x = 5
def y(): return x*2

print(x)
print(y())

x = 3

# Expect it to print '3' and '6' instead it print '3' and '10'
print(x)
print(y())

[0] I know of make's lazy variables and Perl's tied scalars

[1] it does have computed attributes (aka properties) but that's a very different thing

[2] There are situations which kind-of look like dependent variables e.g. if you set y to a mutable sub-structure of x changes to this sub-part of x will be visible through y. That's not actually a dependency though, it's just that the two variables point to the same (mutable) structure, so both "see" mutations applied to that shared structure.




回答2:


The y variable is dependent on x right?

Well, first things first, if you set:

a = 7
b = a
a = 4

Then,

print(id(a)) and print(id(b)), you will get two different ids, hence b will not change when you overwrite a.




回答3:


Your y points to an older version of the x-variable. To update y, you could do:

x = 5
y = x * 2

print(x)
print(y)

x = 3
y = x * 2

print(x)
print(y)

Which will output:

5
10
3
6



回答4:


Because after you assign a value to variable y, in order to change it you will need to access directly to y. y= x*2 is assigning value to y according to what the value of x in this line of code. this how python works, there are other code languages who can preform like u expected. after assigning the new value to x , you will need to write again y=x*2.



来源:https://stackoverflow.com/questions/62042913/why-is-a-variable-not-updating-after-changing-its-dependent-variable

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