Regex split string by last occurrence of pattern

问题

I am using regex to split a string <book name> by <author name> into book and author names.

re.split(r'\bby\b', text, 0, re.I)

But problem arises when the book name contains the word "by" (e.g. Death by Blackhole by Tyson => ['Death', 'by Black...'])

How do I split the string by the last occurrence of the search pattern?

I have a hunch -/+ve look-ahead/behind could be useful here, but currently splitting hairs trying to construct the proper syntax.

回答1:

You could use findall with a greedy .* before the by:

re.findall(r'(.*)\s+by\s+(.*)', text, re.I)

See it on repl.it

回答2:

You can reconstruct from the split:

parts = re.split(r'\bby\b', text, 0, re.I)
book, author = 'by'.join(parts[:-1]), parts[-1]

Or do a complete match:

match = re.match(r'(.*)\bby\b(.*)', text, re.I)

回答3:

You can try this, it will match the last by, tested on your example

by(?!.*by.*)

回答4:

You can use this single regex:

re.search('((.*( by )?.*) by (.*))',text).group(2,4)

来源：https://stackoverflow.com/questions/42733954/regex-split-string-by-last-occurrence-of-pattern