问题
Goal: write a select query that returns all rows where state equals "florida".
Entity column:
@Column({ type: 'json'})
public address: Address;
Sample column value:
{"city": "miami", "state": "florida"}
Example query (doesn't work):
getManager().getRepository(User)
.createQueryBuilder('user')
.select()
.where('user.address.state =:state', {state: "florida"})
Is this functionality currently supported in typeorm? If so, how would I need to modify my where clause to return the correct rows?
回答1:
Got it working.
Correct syntax:
.where(`user.address ::jsonb @> \'{"state":"${query.location}"}\'`)
回答2:
Another possible solution (raw SQL can not be injected with this):
.where('user.address ::jsonb @> :address', {
address: {
state: query.location
}
})
With this, TypeORM will produce an SQL query ending with
WHERE user.address ::jsonb @> $1
and the query will be given e.g.
{ state: 'florida' }
as a query parameter to replace the right value ($1) in the query.
Sources: Mainly the original question + answer (thank you!) + own testing + https://www.postgresql.org/docs/9.4/functions-json.html
回答3:
return getRepository(User)
.createQueryBuilder()
.where('address @> :address', {
address: { state: "florida" },
})
.getMany();
回答4:
This works for me. I just use TypeORM like function.
.find({
where: {
address: Like(`%${add what to search for here}%`),
},
});
来源:https://stackoverflow.com/questions/52808304/typeorm-postgres-select-where-json-field-equals-some-value