问题
This should be quite simple, but I can't manage to read in a floating point number in Fortran. My program test.f looks like this:
PROGRAM TEST
open(UNIT=1,FILE='test.inp')
read(1,'(f3.0)')line
STOP
END
The input file test.inp
simply contains a single float: 1.2
Now the compiling of my testfile goes fine, but when I run it I get an error:
At line 4 of file test.f (unit = 1, file = 'test.inp')
Fortran runtime error: Expected REAL for item 1 in formatted transfer, got INTEGER
(f3.0)
^
I've tried different modifications of the code and also googling for the error message, but with no result. Any help would be greatly appreciated!
Regards, Frank
回答1:
Your variable line
is implicitly defined as integer. This doesn't work with thef
edit descriptor. If you want to read an integer use i
edit descriptor (i3
for example). Otherwise declare line
as real to math the "f" descriptor.
Note beside: the .0 is not a problem, because if Fortran gets a number with decimal point the .0 part in the descriptor is ignored. It is only used when an number without a decimal is entered and then it uses the number behind the decimal point in the desciptor to add a decimal point into the right place. For with F8.5
, 123456789
is read as 123.45678
. More ont this here http://software.intel.com/sites/products/documentation/hpc/compilerpro/en-us/fortran/lin/compiler_f/lref_for/source_files/pghredf.htm .
回答2:
In your read statement
read(1,'(f3.0)')line
the f3.0
tells tour program to read 3 digits with 0 digits after the decimal (this is what the n.m syntax means). So I presume that the program is just reading 1
from the file (not 1.2
), which is an integer. Try replacing that line with something like
read(1,'(f3.1)')line
although, if the number in your file is likely to change and be larger than 9.9 or have more than one decimal place you should increase the field width to something larger than 3.
See the documentation of the read intrinsic and for data edit descriptors for more information on reading and writing in Fortran.
Edit: the format specifier, the second argument in quotes in your read statment, has the form fw.d
, where f
indicates that the data to read is a floating point number, w
is the width of the field including all blanks and decimal points and d
specifies the number of digits to the right of the decimal point.
回答3:
I would suggest reading/writing list formatted data, unless you have a very strong reason to do otherwise. assuming that you're reading in from a file with just a single float or integer in a single line, like this
123.45
11
42
then this should do the reading
real*8 :: x,y,z
open(1,file=filename)
read(1,*)x
read(1,*)y
read(1,*)z
close(1)
来源:https://stackoverflow.com/questions/8477010/error-when-reading-in-float-in-fortran