SwiftUI Dismiss Multiple Modal Sheets

问题

I am using .sheet(isPresented: self.$showModal) in my root view to present a modal. Within the modal, I am using NavigationView to take the user through various pages (for a user profile builder).

In the last page of my navigation stack, I am using @Environment(\.presentationMode) var presentationMode and a button which calls self.presentationMode.wrappedValue.dismiss() to dismiss the modal. However, this only dismisses the last page in the navigation stack, and I just end up at the previous page. What I want to do is dismiss the entire navigation stack and end up back at the root view.

Swiping down to dismiss the modal produces the desired result, but I want to do this programatically with the button.

Is this currently possible in SwiftUI, or is this a problem with using NavigationView within a modal sheet?

回答1:

You can pass showModal as a binding into the following screens and instead of using presentationValue set showModal to false.

回答2:

@State private var modalOpen: Bool = false

.sheet(isPresented: self.$modalOpen, onDismiss: {
            // code that triggers when modal is closed
        }) {
        Button(action: {
            self.modalOpen.toggle()
        }) {
           Text("Schließen")
        }

回答3:

A possible solution is to use a custom EnvironmentKey injected to every environment:

struct PresentationKey: EnvironmentKey {
    static let defaultValue: [Binding<Bool>] = []
}

extension EnvironmentValues {
    var presentations: [Binding<Bool>] {
        get { return self[PresentationKey] }
        set { self[PresentationKey] = newValue }
    }
}

Demo:

struct ContentView: View {
    @Environment(\.presentations) private var presentations
    @State private var showSheet = false

    var body: some View {
        Button("Show sheet") {
            showSheet = true
        }
        .sheet(isPresented: $showSheet) {
            SheetView()
                .environment(\.presentations, presentations + [$showSheet])
        }
    }
}

struct SheetView: View {
    @Environment(\.presentations) private var presentations
    @State private var showSheet = false

    var body: some View {
        Button("Show another sheet") {
            showSheet = true
        }
        .sheet(isPresented: $showSheet) {
            SheetNavigationView()
                .environment(\.presentations, presentations + [$showSheet])
        }
    }
}

struct SheetNavigationView: View {
    var body: some View {
        NavigationView {
            NavigationLink("Link", destination: SheetNavigationDetailView())
        }
    }
}

struct SheetNavigationDetailView: View {
    @Environment(\.presentations) private var presentations

    var body: some View {
        Button("Pop to root") {
            presentations.forEach {
                $0.wrappedValue = false
            }
        }
    }
}

来源：https://stackoverflow.com/questions/58297472/swiftui-dismiss-multiple-modal-sheets

标签

ios

swift

swiftui