数组去重、数组中的对象去重

无人久伴 提交于 2021-01-10 00:37:13
// 数组去重
{
   const arr = [1,2,3,4,1,23,5,2,3,5,6,7,8,undefined,null,null,undefined,true,false,true,‘中文‘,‘‘,‘‘,‘hello‘,‘中文‘];
   //  第一种
   const r = [...new Set(arr)];
   console.log(r); // [1, 2, 3, 4, 23, 5, 6, 7, 8, undefined, null, true, false, "中文", "", "hello"]

   
   // 第二种
   const R = arr.reduce((all,name) => all.includes(name) ? all :[...all,name],[]);
   console.log(R); // [1, 2, 3, 4, 23, 5, 6, 7, 8, undefined, null, true, false, "中文", "", "hello"]
   
   // 第三种
   const k = arr.filter((item, i) => i === arr.indexOf(item));
   console.log(k); // [1, 2, 3, 4, 23, 5, 6, 7, 8, undefined, null, true, false, "中文", "", "hello"]
}


// 统计每个元素在数组中出现的次数
{
   const arr = [‘zhangsan‘, ‘lisi‘, ‘wangwu‘, ‘zhangsan‘, ‘lisi‘, ‘wangwu‘,‘zhaosi‘,‘liuneng‘];
   const r = arr.reduce((all, name) =>{
      if(name in all){
         all[name]++
      }else{
         all[name] = 1;
      }
      return all;
   },{});
   console.log(r); // {zhangsan: 2, lisi: 2, wangwu: 2, zhaosi: 1, liuneng: 1}
}

// 数组对象去重
{
   const arr = [
      {
         name:‘zhangsan‘,
            age:12
      },
        {
         name:‘lisi‘,
         age:14
      },
      {
         name:‘zhangsan‘,
            age:12
      },
        {
         name:‘lisi‘,
         age:14
      },
      {
         name:‘zhangsan‘,
            age:12
      },
        {
         name:‘lisi‘,
         age:14
      },
      {
         name:‘zhangsan‘,
            age:12
      },
        {
         name:‘wangwu‘,
         age:16
      },
      {
         name:‘wagnwu‘,
            age:16
      },
        {
         name:‘lisi‘,
         age:14
      },
      
   ]
   
   // 根据 age 去重
    // 方法一
    const age = ‘age‘;
   const r = arr.reduce((all, next) => all.some((atom) => atom[age] == next[age]) ? all : [...all, next],[]);
   console.log(r);

}

  

标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!