问题
Assume this scenario: page1 Navigator.push to page2. user on page2 clicks the back button, so page2 pops and page1 regains view. How do I catch this event on page1?
回答1:
You can check like this by passing parameter from Navigator.pop...
from the second screen:-
 Navigator.pop(context, 'updateList'),
and on the first screen check like this and pass condition which you want:-
FloatingActionButton(
                  onPressed: () {
                    Navigator.push(
                      context,
                      MaterialPageRoute(
                        builder: (BuildContext context) =>
                            new ManageAssignments(),
                      ),
                    ).then((val) {
                      if (val == 'updateList') getAssignementList();
                    });
                  },
                  backgroundColor: Theme.of(context).primaryColor,
                  child: Icon(Icons.add),
                )
Hope it will work for you :-)
回答2:
So when Navigator.push() happens it returns a Future. And on Navigator.pop() the future is resolved. You can return value from Navigator.pop like this Navigator.pop(context, "MyResult"); That result will be captured like this - final result = Navigator.push(). You can use the result in the widget from where Navigator.push() was called.
回答3:
Use WillPopScope widget in the pop screen, then to get notified when screen is popped use onWillPop function.
Like this:
return WillPopScope(
      child: Scaffold(
          body: new Container(), // your body content
      onWillPop: (){
      //Screen is poped.
    },
    );
    
)
来源:https://stackoverflow.com/questions/58850661/flutter-how-to-get-notified-when-the-page-i-pushed-was-popped-by-back-button