How can I match the root path with a Warp filter?

问题

I have a simple web server using Warp that serves static files. I followed the examples in the Warp docs to get the following:

let index_html = warp::path("index.html").map(handlers::index_html); // reply is handled in `handlers::`

let script_js = warp::path("script.js").map(handlers::script_js);

let routes = warp::get().and(index_html.or(script_js));

warp::serve(routes).run(([127, 0, 0, 1], 8000)).await;

This returns files when requested from localhost:8000/index.html and localhost:8000/script.js.

I want to serve the index file from localhost:8000 rather than /index.html, but I'm not sure how to specify the domain root with warp::path. I've tried replacing warp::path("index.html") with

• warp::path()
• warp::path("")
• warp::path("/")

but with no success.

回答1:

To target the root path use warp::path::end(). The docs have an ambiguously brief description.

For the example above the code for index_html would be replaced with:

let index_html = warp::path::end().map( ... );

来源：https://stackoverflow.com/questions/63003414/how-can-i-match-the-root-path-with-a-warp-filter