问题
I am trying to add done button in number type input for a TextFormField in flutter but I could not able to do that.
TextFormField(
key: Key(keyValue),
initialValue: valueBuilder,
onSaved: (text) {
fieldsController.text = text.trim();
},
inputFormatters: [inputFormatters],
keyboardType: TextInputType.phoneNumber,)
I want create a keyboard like the below. For the input text form field.
回答1:
Change
keyboardType: TextInputType.number
to
keyboardType: TextInputType.numberWithOptions(signed: true, decimal: true)
回答2:
I've just created a package for add basic actions to the current keyboards .
You can take a look here :
https://pub.dartlang.org/packages/keyboard_actions
Usage :
import 'package:flutter/material.dart';
import 'package:keyboard_actions/keyboard_actions.dart';
//...
FocusNode _nodeText1 = FocusNode();
FocusNode _nodeText2 = FocusNode();
FocusNode _nodeText3 = FocusNode();
FocusNode _nodeText4 = FocusNode();
FocusNode _nodeText5 = FocusNode();
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text("Keyboard Actions Sample"),
),
body: FormKeyboardActions(
keyboardActionsPlatform: KeyboardActionsPlatform.ALL, //optional
keyboardBarColor: Colors.grey[200], //optional
nextFocus: true, //optional
actions: [
KeyboardAction(
focusNode: _nodeText1,
),
KeyboardAction(
focusNode: _nodeText2,
closeWidget: IconButton(
icon: Icon(Icons.close),
onPressed: () {},
),
),
KeyboardAction(
focusNode: _nodeText3,
onTapAction: () {
showDialog(
context: context,
builder: (context) {
return AlertDialog(
content: Text("Custom Action"),
actions: <Widget>[
FlatButton(
child: Text("OK"),
onPressed: () => Navigator.of(context).pop(),
)
],
);
});
},
),
KeyboardAction(
focusNode: _nodeText4,
displayCloseWidget: false,
),
KeyboardAction(
focusNode: _nodeText5,
closeWidget: Padding(
padding: EdgeInsets.all(5.0),
child: Text("CLOSE"),
),
),
],
child: Padding(
padding: const EdgeInsets.all(15.0),
child: SingleChildScrollView(
child: Column(
crossAxisAlignment: CrossAxisAlignment.stretch,
children: <Widget>[
TextField(
keyboardType: TextInputType.number,
focusNode: _nodeText1,
decoration: InputDecoration(
hintText: "Input Number",
),
),
TextField(
keyboardType: TextInputType.text,
focusNode: _nodeText2,
decoration: InputDecoration(
hintText: "Input Text with Custom Close Widget",
),
),
TextField(
keyboardType: TextInputType.number,
focusNode: _nodeText3,
decoration: InputDecoration(
hintText: "Input Number with Custom Action",
),
),
TextField(
keyboardType: TextInputType.text,
focusNode: _nodeText4,
decoration: InputDecoration(
hintText: "Input Text without Close Widget",
),
),
TextField(
keyboardType: TextInputType.number,
focusNode: _nodeText5,
decoration: InputDecoration(
hintText: "Input Number with Custom Close Widget",
),
),
],
),
),
),
),
);
}
回答3:
You don't need a done button just wrap MaterialApp with a GestureDetector
GestureDetector(
behavior: HitTestBehavior.opaque,
onTap: () {
FocusScopeNode currentFocus = FocusScope.of(context);
if (!currentFocus.hasPrimaryFocus &&
currentFocus.focusedChild != null) {
FocusManager.instance.primaryFocus.unfocus();
}
},
child: MaterialApp(
title: "My title",
home:MyHomeScreen(),
),
);
回答4:
Please try change to
inputType: const TextInputType.numberWithOptions(signed: true),
inputFormatters: <TextInputFormatter>[
FilteringTextInputFormatter.digitsOnly,
],
回答5:
There is no done button in iOS but we can check the length of the input and clear focus to hide the numberpad keyboard.
Implement like below,(it'll work with fix length of number value)
onChanged: (val) {
if (val.length == 10) { //10 is the length of the phone number you're allowing
FocusScope.of(context).requestFocus(FocusNode());
}
}
来源:https://stackoverflow.com/questions/53505500/flutter-how-to-add-done-button-in-number-keyboard-in-flutter