Python - Take weighted average inside Pandas groupby while ignoring NaN

问题

I need to group a Pandas dataframe by date, and then take a weighted average of given values. Here's how it's currently done using the margin value as an example (and it works perfectly until there are NaN values):

df = orders.copy()
# Create new columns as required
df['margin_WA'] = df['net_margin'].astype(float)    # original data as str or Decimal

def group_wa():
        return lambda num: np.average(num, weights=df.loc[num.index, 'order_amount'])

agg_func = {
        'margin_WA': group_wa(),    # agg_func includes WAs for other elements
    }

result = df.groupby('order_date').agg(agg_func)

result['margin_WA'] = result['margin_WA'].astype(str)

In the case where 'net_margin' fields contain NaN values, the WA is set to NaN. I can't seem to be able to dropna() or filtering by pd.notnull when creating new columns, and I don't know where to create a masked array to avoid passing NaN to the group_wa function (like suggested here). How do I ignore NaN in this case?

回答1:

I think a simple solution is to drop the missing values before you groupby/aggregate like:

 result = df.dropna(subset='margin_WA').groupby('order_date').agg(agg_func)

In this case, no indices containing missings are passed to your group_wa function.

Edit

Another approach is to move the dropna into your aggregating function like:

def group_wa(series):
    dropped = series.dropna()
    return np.average(dropped, weights=df.loc[dropped.index, 'order_amount'])

agg_func = {'margin_WA': group_wa}
result = df.groupby('order_date').agg(agg_func)

来源：https://stackoverflow.com/questions/43049014/python-take-weighted-average-inside-pandas-groupby-while-ignoring-nan