def get_filePath_fileName_fileExt(fileUrl):
"""
获取文件路径， 文件名， 后缀名
:param fileUrl:
:return:
"""
filepath, tmpfilename = os.path.split(fileUrl)
shotname, extension = os.path.splitext(tmpfilename)
return filepath, shotname, extension
来源：oschina
链接：https://my.oschina.net/u/4305185/blog/3848898