Why do -Xmx and Runtime.maxMemory not agree

痞子三分冷 提交于 2019-11-27 20:30:45

问题


When you add

 -Xmx????m

to the command line, the JVM gives you a heap which is close to this value but can be out by up to 14%. The JVM can give you a figure much closer to what you want, but only through trial and error.

 System.out.println(Runtime.getRuntime().maxMemory());

prints

-Xmx1000m ->  932184064
-Xmx1024m -Xmx1g ->  954728448
-Xmx1072m ->  999292928
-Xmx1073m -> 1001390080

I am running HotSpot Java 8 update 5.

Clearly, the heap can be something just above 1000000000 but why is this -Xmx1073m instead of say -Xmx1000m?

BTW 1g == 1024m which suggests that 1g should be 1024^3 which is 7% higher than 1000^3 but you get something 7% lower than 1000^3.


Being off by so much suggests that I am missing something fundamental about how the heap works. If I asked for -Xmx1000m and it was 1001390080 I wouldn't care, I would assume there is some allocation multiple it needs to adhere to, but to give you 932184064 suggests to me the heap is more complicated than I can imagine.


EDIT I have found that

-Xmx1152m gives 1073741824 which is exactly 1024^3

so it appears it is giving me exactly 128 MB less than I asked for in this case cf the maxMemory().


BTW 128 is my favourite number. I was in a conference today at street number 128 and the speaker quoted a book from page 128 ;)


回答1:


The difference appears to be accounted for by the size of the garbage collector's survivor space.

The -Xmx flag, as described in the docs, controls maximum size of the memory allocation pool. The heap portion of the memory allocation pool is divided into Eden, Survivor, and Tenured spaces. As described in this answer, there are two survivor regions, only one of which is available to hold live objects at any given point in time. So the total apparent space available for allocating objects, as reported by Runtime.maxMemory(), must subtract the size of one of the survivor spaces from the total heap memory pool.

You can use the MemoryMXBean and MemoryPoolMXBean classes to get a little more information about your memory allocation. Here's a simple program I wrote:

import java.lang.management.ManagementFactory;
import java.lang.management.MemoryMXBean;
import java.lang.management.MemoryPoolMXBean;

public class MemTest {
  static String mb (long s) {
    return String.format("%d (%.2f M)", s, (double)s / (1024 * 1024));
  }

  public static void main(String[] args) {
    System.out.println("Runtime max: " + mb(Runtime.getRuntime().maxMemory()));
    MemoryMXBean m = ManagementFactory.getMemoryMXBean();

    System.out.println("Non-heap: " + mb(m.getNonHeapMemoryUsage().getMax()));
    System.out.println("Heap: " + mb(m.getHeapMemoryUsage().getMax()));

    for (MemoryPoolMXBean mp : ManagementFactory.getMemoryPoolMXBeans()) {
      System.out.println("Pool: " + mp.getName() + 
                         " (type " + mp.getType() + ")" +
                         " = " + mb(mp.getUsage().getMax()));
    }
  }
}

The output of this on OpenJDK 7 for java -Xmx1024m MemTest is:

Runtime max: 1037959168 (989.88 M)
Non-heap: 224395264 (214.00 M)
Heap: 1037959168 (989.88 M)
Pool: Code Cache (type Non-heap memory) = 50331648 (48.00 M)
Pool: Eden Space (type Heap memory) = 286326784 (273.06 M)
Pool: Survivor Space (type Heap memory) = 35782656 (34.13 M)
Pool: Tenured Gen (type Heap memory) = 715849728 (682.69 M)
Pool: Perm Gen (type Non-heap memory) = 174063616 (166.00 M)

Note that Eden + 2*Survivor + Tenured = 1024M, which is exactly the amount of heap space requested on the command line. Much thanks to @Absurd-Mind for pointing this out.

The differences you observe between different JVMs are likely due to differing heuristics for selecting the default relative sizes of the various generations. As described in this article (applies to Java 6, wasn't able to find a more recent one), you can use the -XX:NewRatio and -XX:SurvivorRatio flags to explicitly control these settings. So, running the command:

java -Xmx1024m -XX:NewRatio=3 -XX:SurvivorRatio=6

You're telling the JVM that:

Young:Tenured = (Eden + 2*Survivor):Tenured = 1:3 = 256m:768m
Survivor:Eden = 1:6 = 32m:192m

So, with these parameters, the difference between the requested -Xmx value and the available memory reported by Runtime.maxMemory() should be 32m, which is verified using the above program. And now you should be able to accurately predict the available memory reported by Runtime for a given set of command-line arguments, which is all you ever really wanted, right?




回答2:


The following graph shows the Runtime.maxMemory as a percentage of Xmx (on the y-axis) for different Xmx values (on the x-axis).

We see that for the most part only ~85% of the Xmx setting is available for the heap to grow. This analysis is conducted using java version "1.8.0_212" Java(TM) SE Runtime Environment (build 1.8.0_212-b10) Java HotSpot(TM) 64-Bit Server VM (build 25.212-b10, mixed mode)

Graph of (maxMem/Xmx) for varying Xmx sizes (in MB)



来源:https://stackoverflow.com/questions/23701207/why-do-xmx-and-runtime-maxmemory-not-agree

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