问题：
This question already has an answer here: 这个问题已经在这里有了答案：
- How to compare strings in Bash 10 answers 如何在Bash中比较字符串 10个答案
I'm trying to get an if statement to work in Bash (using Ubuntu ): 我正在尝试让if语句在Bash中工作（使用Ubuntu ）：
#!/bin/bash
s1="hi"
s2="hi"
if ["$s1" == "$s2"]
then
echo match
fi
I've tried various forms of the if statement, using [["$s1" == "$s2"]] , with and without quotes, using = , == and -eq , but I still get the following error: 我已经尝试过各种形式的if语句，使用[["$s1" == "$s2"]] ，使用和不使用引号，使用= ， ==和-eq ，但是仍然出现以下错误：
[hi: command not found [hi：找不到命令
I've looked at various sites and tutorials and copied those, but it doesn't work - what am I doing wrong? 我查看了各种站点和教程并复制了这些站点和教程，但是它不起作用-我在做什么错？
Eventually, I want to say if $s1 contains $s2 , so how can I do that? 最终，我想说一下$s1包含$s2 ，那我该怎么做呢？
I did just work out the spaces bit.. :/ How do I say contains? 我只是算出空格位..：/我怎么说包含？
I tried 我试过了
if [[ "$s1" == "*$s2*" ]]
but it didn't work. 但这没用。
解决方案：
参考一： https://stackoom.com/question/Hwob/如何在Bash的-if-语句中比较两个字符串变量-重复参考二： https://oldbug.net/q/Hwob/How-do-I-compare-two-string-variables-in-an-if-statement-in-Bash-duplicate
来源：oschina
链接：https://my.oschina.net/u/4438370/blog/4280644