python 实现
def edit_distance(word1, word2):
len1 = len(word1)
len2 = len(word2)
dp = np.zeros((len1 + 1,len2 + 1))
for i in range(len1 + 1):
dp[i][0] = i
for j in range(len2 + 1):
dp[0][j] = j
for i in range(1, len1 + 1):
for j in range(1, len2 + 1):
delta = 0 if word1[i-1] == word2[j-1] else 1
dp[i][j] = min(dp[i - 1][j - 1] + delta, min(dp[i-1][j] + 1, dp[i][j - 1] + 1))
转载于:https://blog.csdn.net/koibiki/article/details/83031788
来源:oschina
链接:https://my.oschina.net/u/4389636/blog/4307850