如何安全地创建嵌套目录？

问题：

What is the most elegant way to check if the directory a file is going to be written to exists, and if not, create the directory using Python? 检查文件目录是否存在的最优雅方法是什么？如果不存在，则使用Python创建目录？ Here is what I tried: 这是我尝试过的：

import os

file_path = "/my/directory/filename.txt"
directory = os.path.dirname(file_path)

try:
    os.stat(directory)
except:
    os.mkdir(directory)       

f = file(filename)

Somehow, I missed os.path.exists (thanks kanja, Blair, and Douglas). 不知何故，我错过了os.path.exists （感谢kanja，Blair和Douglas）。 This is what I have now: 这就是我现在所拥有的：

def ensure_dir(file_path):
    directory = os.path.dirname(file_path)
    if not os.path.exists(directory):
        os.makedirs(directory)

Is there a flag for "open", that makes this happen automatically? 是否有“打开”标志，使它自动发生？

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解决方案：

参考一： https://stackoom.com/question/194K/如何安全地创建嵌套目录
参考二： https://oldbug.net/q/194K/How-can-I-safely-create-a-nested-directory

来源：oschina

链接：https://my.oschina.net/u/4428122/blog/4454454