Fatal error: Uncaught exception 'mysqli_sql_exception' with message 'No index used in query/prepared statement'

问题

When I run the following code, I get the error saying

Fatal error: Uncaught exception 'mysqli_sql_exception' with message 'No index used in query/prepared statement'

$mysql = new mysqli(DB_SERVER, DB_USER, DB_PASSWORD, DB_NAME) or die('There was a problem connecting to the database');
        if (mysqli_connect_errno()) {
            printf("DB error: %s", mysqli_connect_error());
            exit();
        }

    $get_emp_list = $mysql->prepare("SELECT id, name FROM calc");
    if(!$get_emp_list){
        echo "prepare failed\n";
        echo "error: ", $mysql->error, "\n";
        return;
    }
    $get_emp_list->execute();
    $get_emp_list->bind_result($id, $emp_list);

And this is the able schema --

--
-- Table structure for table `calc`
--

CREATE TABLE IF NOT EXISTS `calc` (
  `id` int(12) NOT NULL,
  `yr` year(4) NOT NULL,
  `mnth` varchar(12) NOT NULL,
  `name` varchar(256) NOT NULL,
  `paidleave` int(12) NOT NULL,
  `balanceleave` int(12) NOT NULL,
  `unpaidleave` int(12) NOT NULL,
  `basesalary` int(12) NOT NULL,
  `deductions` int(12) NOT NULL,
  `tds` int(12) NOT NULL,
  `pf` int(12) NOT NULL,
  `finalsalary` int(12) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;

回答1:

Take a look at this bug-report : #35450 mysqli extension reports too many warnings

Quoting a few sentences of a note :

Mysqli extension throws too many warnings.
For example, "SELECT * FROM table" results in a warning: "Warning: mysqli::query(): No index used in query/prepared statement SELECT * FROM table ..."

And, quoting another note, which seems interesting :

Use mysqli_report() to disable that.

回答2:

The fatal error is not in MySQL; the missing index notification is a relatively low-severity warning.

The fatal error is in your PHP code, because of the following three conditions:

mysqli reports a lot of warnings, even for relatively harmless conditions.
You're throwing mysqli_sql_exception for all errors and warnings due to your mysqli_report(MYSQLI_REPORT_ALL); line.
Your PHP code is not catching that exception (i.e. it's not in a try{} block with an appropriate catch(){} block), and uncaught exceptions are fatal.

You can't do much about the first one, as mentioned in the other answer. So, you can fix it either by changing your mysqli_report(...) setting to MYSQLI_REPORT_STRICT or MYSQLI_REPORT_OFF, or indeed anything other than MYSQLI_REPORT_ALL.

(edit: w3d's comment below gives a good explanation why, and suggests you could use mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT) as a good alternative)

For best practices, and in combination with this, you should fix it properly by using try{} and catch(){} appropriately within your code.

回答3:

mysqli_report(MYSQLI_REPORT_ALL ^ MYSQLI_REPORT_INDEX);

Turns off "Report if no index or bad index was used in a query" yet keeps other reporting on.

回答4:

Another way to fix it is to make your table column 'name' in MySQL an index.

ALTER TABLE `calc` ADD INDEX ( `name` ) ;

来源：https://stackoverflow.com/questions/62961375/why-prepared-statement-fails-to-select-using-mysqli-stmt-bind-result

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