Gulpfile.js failed to load

一个人想着一个人 提交于 2020-07-20 08:37:26

问题


Visual Studio task runner cannot load the gulp file. I use VS2017 v15.9.4 now, however, the project developed some years ago.

Failed to run "...\Gulpfile.js"...
cmd.exe /c gulp --tasks-simple
assert.js:350
    throw err;
    ^
AssertionError [ERR_ASSERTION]: Task function must be specified
    at Gulp.set [as _setTask] (...\node_modules\undertaker\lib\set-task.js:10:3)
    at Gulp.task (...\node_modules\undertaker\lib\task.js:13:8)
    at Object.<anonymous> (...\gulpfile.js:34:6)
    at Module._compile (internal/modules/cjs/loader.js:689:30)
    at Object.Module._extensions..js (internal/modules/cjs/loader.js:700:10)
    at Module.load (internal/modules/cjs/loader.js:599:32)
    at tryModuleLoad (internal/modules/cjs/loader.js:538:12)
    at Function.Module._load (internal/modules/cjs/loader.js:530:3)
    at Module.require (internal/modules/cjs/loader.js:637:17)
    at require (internal/modules/cjs/helpers.js:22:18)

I replaced my project local address by "..."

npm -v --> 6.4.1

node -v --> 10.14.2

gulp -v --> CLI version 2.0.1
            Local version 4.0.0

The content of package.json file:

{
  "version": "1.0.0",
  "name": "tratic",
  "private": true,
  "devDependencies": {
    "gulp": "github:gulpjs/gulp#4.0",
    "gulp-clean-css": "3.5.0",
    "gulp-concat": "2.6.1",
    "gulp-durandal": "1.1.7",
    "gulp-install": "^1.1.0",
    "gulp-uglify": "3.0.0",
    "gulp-util": "3.0.8",
    "rimraf": "2.6.1"
  },
  "dependencies": {
    "assert": "^1.4.1",
    "assert-js": "^0.20.0",
    "natives": "^1.1.5"
  },
  "scripts": {
    "gulp": "./node_modules/gulp/bin/gulp.js"
  }
}

The content of gulpfile.js:

var gulp = require('gulp'),
    durandal = require('gulp-durandal'),
    rimraf = require('rimraf');

gulp.task('clean', function (cb) {
    rimraf('app/main-built.js', cb);
});

gulp.task('durandal', ['clean'], function () {
    durandal({
        baseDir: 'app',
        main: 'main.js',
        output: 'main-built.js',
        almond: true,
        minify: true
    })
    .pipe(gulp.dest('app'));
});

gulp.task('default', ['durandal']);

I google it and the existing solutions cannot solve the problem. There are some related issue but does not work for me.

How can I solve the problem?


回答1:


I have tried your setup, it indeed threw an error like yours. I went to the gulp docs and tried their version of a gulpfile, and it worked with no issues. So I have rewritten your gulpfile to match their example and it worked well. here's the code:


    var gulp = require('gulp'),
        durandal = require('gulp-durandal'),
        rimraf = require('rimraf');

    var paths = {
        app: "./App/**/*.js",
        js: "./Scripts/**/*.js",
        css: "./Content/**/*.css",
        concatJsDest: "./Scripts/vendor-scripts.min.js",
        concatCssDest: "./Content/vendor-css.min.css"
    };

    function clean (cb) {
      rimraf('app/main-built.js', cb);
    }

    gulp.task('clean', clean);

    function runDurandal () {
      return durandal({
          baseDir: 'app',
          main: 'main.js',
          output: 'main-built.js',
          almond: true,
          minify: true,
          rjsConfigAdapter: function (rjsConfig) {
              rjsConfig.deps = ['text'];
              return rjsConfig;
          }
      })
      .pipe(gulp.dest('app'));
    }

    var build = gulp.series(clean, runDurandal);

    gulp.task('default', build);

Basically I have moved functions that you use as tasks to variables, and used series to run durandal.

then I have tried npx gulp --tasks-simple and have a proper output

clean
default

btw, have a look at npx so you don't have to install gulp globally.

Hope that helps!




回答2:


This syntax is no longer allowed in gulp4:

gulp.task('default', ['durandal']);

Use :

gulp.task('default', gulp.series('durandal'));

Likewise change to:

gulp.task('durandal', gulp.series('clean', function (done) {
    durandal({
        baseDir: 'app',
        main: 'main.js',
        output: 'main-built.js',
        almond: true,
        minify: true
    })
    .pipe(gulp.dest('app'));
    done();
});

Also, using pump would probably give you better error reporting than you are getting without it.




回答3:


Try to use this workaround: https://github.com/ampproject/docs/issues/793 Downgrade gulp to this version 3.9.1.



来源:https://stackoverflow.com/questions/53860173/gulpfile-js-failed-to-load

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