问题
I'm taking a reference from : Spring Data Mongo - Perform Distinct, but doesn't wants to pull embedded documents in results and asking another questions.
I want to find technology list where "subdeptCd" : "1D". How can we do that ?
{
"firstName" : "Laxmi",
"lastName" : "Dekate",
.....
.......
.....
"departments" : {
"deptCd" : "Tax",
"deptName" : "Tax Handling Dept",
"status" : "A",
"subdepts" : [
{
"subdeptCd" : "1D",
"subdeptName" : "Tax Clearning",
"desc" : "",
"status" : "A"
"technology" : [
{
"technologyCd" : "4C",
"technologyName" : "Cloud Computing",
"desc" : "This is best certficate",
"status" : "A"
}
]
}
]
},
},
{
"firstName" : "Neha",
"lastName" : "Parate",
.....
.......
.....
"departments" : {
"deptCd" : "Tax Rebate",
"deptName" : "Tax Rebate Handling Dept",
"status" : "A",
"subdepts" : [
{
"subdeptCd" : "1D",
"subdeptName" : "Tax Clearning",
"desc" : "",
"status" : "A"
"technology" : [
{
"technologyCd" : "9C",
"technologyName" : "Spring Cloud",
"desc" : "This is best certficate post Google",
"status" : "A"
}
]
}
]
},
}
回答1:
You can get distinct technologies (technology
array elements) with this aggregation:
db.depts.aggregate( [
{
$unwind: "$departments.subdepts"
},
{
$unwind: "$departments.subdepts.technology"
},
{
$match: { "departments.subdepts.subdeptCd": "1D" }
},
{
$group: { _id: "$departments.subdepts.technology.technologyCd", tech: { $first: "$departments.subdepts.technology" } }
},
{
$replaceRoot: { newRoot: "$tech" }
}
] )
来源:https://stackoverflow.com/questions/62260287/spring-data-mongo-how-to-get-the-nested-distinct-array-for-nested-value