Sequelize - function on column in a where clause

问题

I have a Restaurant model with a property 'location' of the type GEOMETRY("Point"). I'm trying to write a query with sequelize that will give me all the restaurants in a certain radius:

models.Restaurant.findAll({
    attributes: ["*", [models.sequelize.fn("ST_Distance_Sphere", models.sequelize.fn("ST_MakePoint", latitude, longitude), models.sequelize.col("location")), "distance"]],
    where: {
        xxx: {
            $lte: radius
        }
    }
}).then(function(dishes) {
    res.status(200).json({dishes: dishes})
});

I have no clue what I should write where xxx is. I have tried all kinds of things but get an error every time. In the select query I'm first calling a function to create a point from the coordinates (latitude, longitude) where to user currently is. Then I use a function to calculate the distance to the location of the restaurant.
I'm using postgres btw.

Edit: Ended up doing it like this:

models.Restaurant.findAll({
    attributes: [
      'id',
      'name',
      'addressLine1',
      'addressLine2',
      'city',
      'zipPostalCode',
      'location',
      'phoneNumber',
      'website',
      [
        models.sequelize.fn(
          'ST_Distance_Sphere', models.sequelize.fn('ST_MakePoint', lat, long), models.sequelize.col('location')
        ),
        'distance',
      ],
    ],
    where: models.sequelize.and(
      models.sequelize.where(
        models.sequelize.fn(
          'ST_Distance_Sphere', models.sequelize.fn('ST_MakePoint', lat, long), models.sequelize.col('location')
        ), '>', fromRadius),
      models.sequelize.where(
        models.sequelize.fn(
          'ST_Distance_Sphere', models.sequelize.fn('ST_MakePoint', lat, long), models.sequelize.col('location')
        ), '<=', toRadius),
      models.sequelize.where(
        models.sequelize.col('Restaurant.is_online'), true
      )
    ),
  })

回答1:

I'm assuming radius is that calculated point where the user is, xxx should be distance

Check the doc, notice the last query:

Model.findAll({
     where: sequelize.where(sequelize.fn('FUNCTION',
            sequelize.col('field')), 'value')
});

来源：https://stackoverflow.com/questions/41579156/sequelize-function-on-column-in-a-where-clause

标签

node.js

postgresql

sequelize.js