Sequelize How compare year of a date in query

问题

I'm trying to make this query:

SELECT * FROM TABLEA AS A WHERE YEAR(A.dateField)='2016'

How can I perfome this query above in sequelize style?

TABLEA.findAll({
      where:{}//????
     }

Thanks!

回答1:

TABLEA.findAll({
  where: sequelize.where(sequelize.fn('YEAR', sequelize.col('dateField')), 2016)
 });

You have to use .where here, because the lefthand side of the expression (the key) is an object, so it cannot be used in the regular POJO style as an object key.

If you want to combine it with other conditions you could do:

TABLEA.findAll({
  where: {
    $and: [
      sequelize.where(sequelize.fn('YEAR', sequelize.col('dateField')), 2016),
      { foo: 'bar' }
    ]
  }
 });

https://sequelize.org/v3/docs/querying/#operators

回答2:

you have to add the date_part function to your query:

sequelize.where(sequelize.fn("date_part",'year',sequelize.col('dateField')), 2020)

回答3:

TABLE.findAll({
  where: sequelize.where(sequelize.fn('YEAR', sequelize.col('dateField')), 2016)
 });

You have to use .where here, because the lefthand side of the expression (the key) is an object, so it cannot be used in the regular POJO style as an object key.

If you want to combine it with other conditions you could do:

var Sequelize require('sequelize')
var Op = Sequelize.Op
let andOp = Op.and

TABLE.findAll({
  where: {
     foo: 'bar',
     andOp:sequelize.where(sequelize.fn('YEAR', sequelize.col('dateField')), 2016)   
  }
 });

https://sequelize.org/v5/manual/querying.html#operators

来源：https://stackoverflow.com/questions/38861087/sequelize-how-compare-year-of-a-date-in-query

标签

javascript

mysql

node.js

datetime

sequelize.js