问题
After checking this Ruby convert array to nested hash and other sites I am not able to achieve the following convertion:
I have this:
{"a"=>"text"}
{"b"=>{"x"=>"hola"}}
{"b"=>{"y"=>"pto"}
}
and I want to obtain:
{"a"=>text,
b=>{"x" => "hola",
"y" => "pto"
}
}
Until now the code seems like this:
tm =[[["a"],"text"],[["b","x"],"hola"],[["b","y"],"pto"]]
q = {}
tm.each do |l|
q = l[0].reverse.inject(l[1]) { |p, n| { n => p } }
i += 1
end
I tried with merge, but it overwrites the keys!. I tried also this How can I merge two hashes without overwritten duplicate keys in Ruby? but it keeps overwritting.
Update:
How can I do it for an undefined nested hash (level) ? hash[key1][key2][key3]... = "value"
{"a"=>"text"},
{"b"=>{"x"=>"hola"},
{"b"=>{"y"=>"pto"},
{"c"=>{"g"=>{"k" => "test1"}},
...
}
回答1:
For Rails there is the deep_merge function for ActiveSupport that does exactly what you ask for.
You can implement the same for yourself as follows:
class ::Hash
def deep_merge(second)
merger = proc { |key, v1, v2| Hash === v1 && Hash === v2 ? v1.merge(v2, &merger) : v2 }
self.merge(second, &merger)
end
end
Now,
h1 = {"a"=>"text"}
h2 = {"b"=>{"x"=>"hola"}}
h3 = {"b"=>{"y"=>"pto"}}
h1.deep_merge(h2).deep_merge(h3)
# => {"a"=>"text", "b"=>{"x"=>"hola", "y"=>"pto"}}
回答2:
You could use merge with a block to tell Ruby how to handle duplicate keys:
a = {"a"=>"text"}
b = {"b"=>{"x"=>"hola"}}
c = {"b"=>{"y"=>"pto"}}
a.merge(b).merge(c) { |key, left, right| left.merge(right) }
#=> {"a"=>"text", "b"=>{"x"=>"hola", "y"=>"pto"}}
来源:https://stackoverflow.com/questions/32268739/merge-nested-hash-without-overwritting-in-ruby