问题
someone please help, i want to transfer all to contents from url to a html file can someone help me please? I have to use user-agent too!
回答1:
because I don't know what site you need scrape so I say a few wasy
if site contains JS frontend and for laoding needed waiting then I recommend you use requests_html module which has method for rendering content
from requests_html import HTMLSession
url = "https://some-url.org"
with HTMLSession() as session:
response = session.get(url)
response.html.render() # rendering JS code
content = response.html.html # full content
if site doesn't use JS for frontent then requests module is really good choice for you
import requests
url = "https://some-url.org"
response = requests.get(url)
content = response.content # html content in bytes()
else you can use selenium webdriver but it works few slowly for python
回答2:
Welcome to SO, when you ask a question you need to submit the code that you have tried, here's where you can learn to ask a question properly. Regarding your question, when you say "I want to transfer all to contents from url to a html file" I am assuming you just want to read the page source and save it in a file.
import requests as r
from bs4 import BeautifulSoup
data = r.get("http://example.com", headers={'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:47.0) Gecko/20100101 Firefox/47.0')
soup = BeautifulSoup(data.text)
file = open('myfile.html', 'w')
file.writelines(soup)
file.close()
if you get an error called TypeError: write() argument must be str, not Tag, just typecast soup to string.
file.writelines(str(soup))
来源:https://stackoverflow.com/questions/62394852/python-get-all-the-contents-from-a-website-to-html-file