问题
This is a follow up to my earlier question.
I wanted to compare the results I get back from filling out a form.
This is what I have so far:
const eqObj = (obj, source) =>
Object.keys(source).every(key => obj.hasOwnProperty(key) && obj[key] === source[key]);
$('#btn').on('click', function() {
let $inputs = $('#new_form :input');
let new_vals = {};
$inputs.each(function() {
new_form[this.id] = $(this).val();
});
console.log(new_vals);
$.getJSON(api, function(data) {
data.forEach(d => {
console.log(d.values);
if (eqObj(new_vals, d.values){//open first models and append matched values}
else {//open other modal}
});
});
});
My console.log() for new_vals: {start_date: "2019-12-25", end_date: "2020-04-15"}
my console.log() for d.values:
{start_date: "2020-01-01", end_date: "2020-03-15"}
{start_date: "2020-01-01", end_date: "2020-03-15"}
{start_date: "2019-12-25", end_date: "2020-04-15"}
{start_date: "2020-03-20", end_date: "2020-03-31"}
{start_date: "2019-10-01", end_date: "2020-03-31"}
{start_date: "2019-10-01", end_date: "2020-03-31"}
{start_date: "2020-01-01", end_date: "2020-01-31"}
{start_date: "2020-01-19", end_date: "2020-01-25"}
When I enter the unmatched values, I am able to open the second modal as I want, but when I enter the matched value in my form, it opens both modals.
Why are both modals opening in my if statement? Is there any way I just do the $.getJSON() in my if statement? I don't need it? I only need the $.getJson() if there are matches, if not I need to open another modal.
回答1:
You probably need to improve your if statement. If you want to show one or another modal only and never both you need to return as soon as the match happens. Try this:
data.forEach(d => {
console.log(d.values);
if (eqObj(new_run_vals, d.values) {
//open first models and append matched values;
return;
}
//open other modal
});
来源:https://stackoverflow.com/questions/62073555/if-compared-values-are-true-then-getjson