How to go about formatting 1200 to 1.2k in Android studio

问题

I'd like to format following numbers into the numbers next to them with Android:

1000 to 1k 5821 to 5.8k 2000000 to 2m 7800000 to 7.8m

回答1:

This should do the trick

String numberString = "";
if (Math.abs(number / 1000000) > 1) {
   numberString = (number / 1000000).toString() + "m";

} else if (Math.abs(number / 1000) > 1) {
   numberString = (number / 1000).toString() + "k";

} else {
   numberString = number.toString();

}

回答2:

Try this trick:

 private String numberCalculation(long number) {
    if (number < 1000) 
        return "" + number;
    int exp = (int) (Math.log(number) / Math.log(1000));
    return String.format("%.1f %c", number / Math.pow(1000, exp), "kMGTPE".charAt(exp-1));
}

回答3:

Function

public String prettyCount(Number number) {
    char[] suffix = {' ', 'k', 'M', 'B', 'T', 'P', 'E'};
    long numValue = number.longValue();
    int value = (int) Math.floor(Math.log10(numValue));
    int base = value / 3;
    if (value >= 3 && base < suffix.length) {
        return new DecimalFormat("#0.0").format(numValue / Math.pow(10, base * 3)) + suffix[base];
    } else {
        return new DecimalFormat("#,##0").format(numValue);
    }
}

Use

prettyCount(789); Output: 789
prettyCount(5821); Output: 5.8k
prettyCount(101808); Output: 101.8k
prettyCount(7898562); Output: 7.9M

回答4:

Try this method :

For Java

public static String formatNumber(long count) {
    if (count < 1000) return "" + count;
    int exp = (int) (Math.log(count) / Math.log(1000));
    return String.format("%.1f %c", count / Math.pow(1000, exp),"kMGTPE".charAt(exp-1));
}

For Kotlin(Android)

fun getFormatedNumber(count: Long): String {
if (count < 1000) return "" + count
val exp = (ln(count.toDouble()) / ln(1000.0)).toInt()
return String.format("%.1f %c", count / 1000.0.pow(exp.toDouble()), "kMGTPE"[exp - 1])
}

来源：https://stackoverflow.com/questions/41859525/how-to-go-about-formatting-1200-to-1-2k-in-android-studio

标签

android

android-studio